Question

A body initially moving at 18 km/h accelerates uniformly with 5 m/s2 for 8 sec .Find the final velocity and the distance covered.

Answer 1

Answer:

We will apply first equation of motion.....

(V=U+AT).....

V=5+5xt...

V=10t....

::: Now, we have to find the distance....

:::(S=UT+1/2AT^2)

S= 5x10+1/2x5x100...

S=50m+250m...

S=300m....

Answer 2

Answer:

v=45m/s

s=200m

Explanation:

Given-

u=18km/h

a=5m/s²

t=8 sec

To Find

v&s

Solution-

To find V --

1. Convert initial velocity to it's SI unit
2. 18km/h * 5/18 = 5m/s

Now using Kinemetic equation

• v=u+at
• v=5+5×8
• v=5+40
• v=45m/s

To Find S--

By using Kinemetic equation-

• s=ut+1/2at²
• s=5×8+1/2×5×8×8
• s=40+160
• s=200m

Thanks---------------