Question

a body initially moving with a speed of 18 kmph is accelerated uniformly at the rate of 9cm/s^2 covers a distance of 200 m calculate final velocity​

Answer 1

Step-by-step explanation:

Given, initial velocity u =18kmh^-1

= 1800m/60x60 s

=5ms^−1

Acceleration a=0.09ms^−2

and distance s = 200 m

From equation of motion v² = u² + 2as

We get, v² = (5m/s)²+2*(0.09m/s²)*200m

v = 7.81 m/s [ANS.]

I hope it may help you.