Question

a body initially starts moving with a constant acceleration of 2m/s^2. calculate the velocity acquired and distance travelled in 5s

Answer 1

u = 0m/s
t = 5s
a = 2m/s²
using first equation of motion
v=u+at
v= 0+(2)(5)
v = 10 m/s

using second equation of motion
s=ut +1/2at²
s = 0(5)+1/2(2)(5)²
s = 0+1/2(2)(25)
s = 25 m
hope this helps

Answer 2

using 1st eqn of motion
v=at
v=2*5
v=10
using 2nd eqn of motion
s=ut+1\2at2
=0+1\2*2*25
=25m