Question

a body initialy at rest travels a distance 50 m in 5 s with a constant acceleration.
calculate:
1) the acceleration
2) the final velocity at the end of 5 s​

Answer 1

Given:-

→Initial velocity of the body = 0

(as it was initially at rest)

→Distance travelled by the body = 50m

→Time taken = 5s

To find:-

→Acceleration

→Final velocity at the end of 5s

Solution:-

By using the 2nd equation of motion,we get:-

=>s = ut+1/2at²

=>50 = 0(5)+1/2×a×(5)²

=>50 = 1/2×a×25

=>50 = 12.5a

=>a = 50/12.5

=>a = 4m/s²

Hence,we have got acceleration as 4m/s².

Now,by using 1st equation if motion,we get:-

=>v = u+at

=>v = 0+(4)5

=>v = 20m/s

Thus:-

•Acceleration of the body is 4m/s².

•Final velocity at the end of 5s is 20m/s.

Some Extra Information:-

The 3 equations of motion, for a body moving with uniform acceleration are:-

•v = u+at

•s = ut+1/2at²

•v²-u² = 2as