Question

A body
Intersect
has lost
10 kg it is
moved
by a horizontal
force of 5N on a
horizontal
Surface
calculate the
work done
by the force
in 8 sec.
​

Answer 1

force =m(v-u)/t

5=10(v-0)/8

5/10*8=v

4=v

a=(v-u)/t

a=4-0/8

a=4/8

a=1/2

s=ut+1/2at^2

s=0*8+1/2*1/2*8*8

s=16

work =force *displacement

work =5*16

work done=80