Physics, asked by itsmeLakshita, 1 month ago

A body is accelerated uniformly from 12 m/s to 37 m/s in 5 seconds. If the mass of the body is 5 kg, and continues to be in uniform acceleration, find the following a. Force acting on the body b. velocity of the body at the end of 8 seconds.​

Answers

Answered by Dwitha
0

Answer:

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Answered by AestheticSky
7

Concept : we are provided with a body of mass 5kg that is uniformly accelerated from 12 m/s to 37 m/s in about 5 seconds. Firstly we are asked to find the force acting on the body. So to calculate that we'll first find acceleration by using the 1st kinematical equation of motion and then it'll be multiplied with the mass in order to get the required value. Secondly, we have to find the velocity at the end of 8 seconds. So we'll just substitute the given values again in the 1st kinematical equation to find the answer.

Given :

➣ Initial Velocity (u) = 12 m/s

➣ Final Velocity (v) = 37 m/s

➣ Time Interval ₁ (t₁) = 5 seconds

➣ Mass (m) = 5 kg

➣ Time Interval ₂ (t₂) = 8 seconds

By using the 1st Kinematical equation:-

  • v = u + at

\\\quad\longrightarrow\quad\tt 37 = 12 + a(5)\\

\quad\longrightarrow\quad\tt 15 = 5a\\

\quad\longrightarrow\quad \boxed{\frak{ a = 3m/s^{2} } }\bigstar\\

Now, substitute this value in the formula of force:

  • F = m × a

\quad\longrightarrow\quad\tt F = 5 \times 3 \\

\quad\longrightarrow\quad\boxed{\bf F = 15 N}\bigstar\\

To solve the 2nd part of the question we are supposed to substitute the values of Initial velocity, uniform acceleration and (t₂) in the 1st kinematical equation:

  • v = u + at

\quad\longrightarrow\quad\tt v = 12 + 3(8)\\

\quad\longrightarrow\quad\tt v = 12 + 24 \\

\quad\longrightarrow\quad\boxed{\sf v = 36 m/s}\bigstar\\

Those are the required answers!!

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