Physics, asked by kapoornaman7430, 1 year ago

A body is accelerating at a constant rate of 10 m/s2 .if the body starts from rest, how much distance covered in 2sec

Answers

Answered by Rosedowson
3
Hi...

Given : u= 0 ms ^-1
a=10ms ^-2
t=2 sec

To find : s = ?

Formula : s = u * t + 0.5 a * t^2

Solution : s = u * t + 0.5 a * t ^2
s = 0 + 0.5 * 10 * 2 ^2
s = 40 m..


Thus distance covered in 2 sec is 40m...

Hope this helps u!!!
Answered by Anonymous
2

Let the initial velocity be = u

Let the final velocity be = v

Let the acceleration be = a

Let the time be = t

Let the displacement be = s

S = ut + 1/2 at^2

S = 0*2 + 1/2*10*2*2

S = 0 + 20

S = 20 m

Therefore distance travelled = 20m

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