A body is accelerating at a constant rate of 10 m/s2 .if the body starts from rest, how much distance covered in 2sec
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Answered by
3
Hi...
Given : u= 0 ms ^-1
a=10ms ^-2
t=2 sec
To find : s = ?
Formula : s = u * t + 0.5 a * t^2
Solution : s = u * t + 0.5 a * t ^2
s = 0 + 0.5 * 10 * 2 ^2
s = 40 m..
Thus distance covered in 2 sec is 40m...
Hope this helps u!!!
Given : u= 0 ms ^-1
a=10ms ^-2
t=2 sec
To find : s = ?
Formula : s = u * t + 0.5 a * t^2
Solution : s = u * t + 0.5 a * t ^2
s = 0 + 0.5 * 10 * 2 ^2
s = 40 m..
Thus distance covered in 2 sec is 40m...
Hope this helps u!!!
Answered by
2
Let the initial velocity be = u
Let the final velocity be = v
Let the acceleration be = a
Let the time be = t
Let the displacement be = s
S = ut + 1/2 at^2
S = 0*2 + 1/2*10*2*2
S = 0 + 20
S = 20 m
Therefore distance travelled = 20m
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