Physics, asked by anoopvenurenu626, 5 hours ago

A body is accelerating at a constant rate of 10m per second squared. If the body starts from rest, then how much distance will it cover in 2 seconds?​

Answers

Answered by PopularAnswerer01
34

Question:-

  • A body is accelerating at a constant rate of 10m per second squared. If the body starts from rest, then how much distance will it cover in 2 seconds ?

To Find:-

  • Find the distance it will cover in 2 seconds.

Solution:-

Given ,

  • A body is accelerating constantly at a rate of 10 m/s²

  • The body starts from rest.

  • It travels for 2 seconds.

Now ,

We have to find the distance travelled in 2 seconds:-

\dashrightarrow\sf \: s = ut + \dfrac { 1 } { 2 } a { t }^{ 2 }

\dashrightarrow\sf \: s = 0( 2 ) + \dfrac { 1 } { 2 } \times 10 \times { 2 }^{ 2 }

\dashrightarrow\sf \: s = \dfrac { 1 } { \cancel { 2 } } \times { \cancel { 10 }}^{ 5 } \times 4

\dashrightarrow\sf \: s = 5 \times 4

\dashrightarrow\sf \: s = 20 \: m

Hence ,

  • Distance travelled is 20 m.
Answered by AestheticSoul
14

Given :

• A body is accelerating at a constant rate of 10 m/s²

• The body starts from rest.

• Time = 2 seconds

To find :

• Distance the body will cover in 2 seconds

Solution :

We have,

• Acceleration of the body = 10 m/s²

• Initial velocity of the body = 0 m/s [Because the body starts from rest.]

• Time = 2 seconds

We can find the the distance the body will travel in 2 seconds by using two methods :-

First method :-

First equation of motion :-

  • v = u + at

where,

• v denotes the final velocity

• u denotes the initial velocity

• a denotes the acceleration

• t denotes the time

Substituting the given values :-

⟶ v = 0 + (10)(2)

⟶ v = 20

Therefore, the final velocity of the body = 20 m/s

Third equation of motion :-

  • v² - u² = 2as

where,

• s denotes the distance/displacement

Substituting the given values :-

⟶ (20)² - (0)² = 2(10)(s)

⟶ 400 = 20 × s

⟶ 400/20 = s

⟶ 20 = s

Therefore, the distance travelled by the body in 2 seconds = 20 m

Second method :-

Second equation of motion :-

  • s = ut + ½ at²

Substituting the given values :-

⟶ s = (0)(2) + ½ × 10 × (2)²

⟶ s = 0 + 5 × 4

⟶ s = 20

Therefore, the distance travelled by the body in 2 seconds = 20 m

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