A body is accelerating at a constant rate of 10ms-2 if the body start from rest how much distance will it cover in 2s
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Answered by
8
acceleration, a = 10 m/s²
if the body starts from rest,
initial velocity, u = 0
time, t = 2s
let distance covered = s
s = ut + 1/2 at²
= 0×2 + 1/2 × 10 × 4²
= 0 + 20
= 20m
It will cover 20m in 2s.
if the body starts from rest,
initial velocity, u = 0
time, t = 2s
let distance covered = s
s = ut + 1/2 at²
= 0×2 + 1/2 × 10 × 4²
= 0 + 20
= 20m
It will cover 20m in 2s.
Answered by
1
a=10ms-2;
u=0
t=2s
s=ut+1/2 at²=1/2*10*4^2 = 20m
It will cover 20m
u=0
t=2s
s=ut+1/2 at²=1/2*10*4^2 = 20m
It will cover 20m
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