Question

A body is accelerating at a constant seed of 10m/sec.². If the body starts at rest how mush distance Will it covered in 2 sec.​

Answer 1

Answer:

The distance covered in 2 sec is 20 m. Hence, The distance covered in 2 sec is 20 m

Explanation:

Acceleration a = 10 m/s²

Initial velocity u = o

Time t = 2

Using equation of motion

s = ut+ 1/2 at²

Where, u = initial velocity

s = distance

t = time

a = acceleration

We substitute the value in equation (I)  

s = 0+1/2 x 10 x 2 x 2

s = 20m  

Hence, The distance covered in 2 sec is 20 m.

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Answer 2

Given:-

☞Acceleration = 10m/s²

☞Time taken = 2sec

☞Initial velocity = 0m/s

To find:-

☞Distance covered-?

Formula to be used:-

☞ $\boxed{\bf{ s= ut + \dfrac{1}{2} a t^2 }}$

where,

s= distance covered

u= initial velocity

t= time

a=acceleration

 

Solution:-

☞By using 2nd equation of motion,

i.e,

$\sf{ s= ut + \dfrac{1}{2} a t^2 }$

Put given values,

$\sf{ \implies s= 0\times 2+ \dfrac{1}{2}\times 10 \times 2^2 }$

$\sf{\implies s= \dfrac{1}{2} \times 10 \times 4}$

$\sf {\implies s= 5\times 4}$

$\sf{\implies s= 20}$

 

$\bf{\underline{\therefore Distance \ covered \ by \ body \ is \ 20m}}$.