Question

A body is accelerating at a constant seed of 10m/sec.². If the body starts at rest how mush distance Will it covered in 2 sec.​

Answer 1

GiveN :

• Acceleration (a) = 10 m/s²
• Initial velocity (u) = 0 m/s
• Time interval (t) = 2s

To FinD :

• Distance travelled by body

SolutioN :

Use 2nd equation of motion :

➛ s = ut + ½at²

⇒s = 0(2) + ½ * 10 * 2²

⇒s = 0 * ½ * 10 * 4

⇒s = 10 * 2

⇒s = 20 m

$\therefore$ Distance covered by body is 20 m.

Answer 2

Answer:

The distance covered in 2 sec is 20 m. Hence, The distance covered in 2 sec is 20 m

Explanation:

Acceleration a = 10 m/s²

Initial velocity u = o

Time t = 2

Using equation of motion

s = ut+ 1/2 at²

Where, u = initial velocity

s = distance

t = time

a = acceleration

We substitute the value in equation (I)  

s = 0+1/2 x 10 x 2 x 2

s = 20m

Hence, The distance covered in 2 sec is 20 m.

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