A body is accelerating at a constant seed of 10m/sec.². If the body starts at rest how mush distance Will it covered in 2 sec.
Answers
Answered by
13
GiveN :
- Acceleration (a) = 10 m/s²
- Initial velocity (u) = 0 m/s
- Time interval (t) = 2s
To FinD :
- Distance travelled by body
SolutioN :
Use 2nd equation of motion :
➛ s = ut + ½at²
⇒s = 0(2) + ½ * 10 * 2²
⇒s = 0 * ½ * 10 * 4
⇒s = 10 * 2
⇒s = 20 m
Distance covered by body is 20 m.
Answered by
0
Answer:
The distance covered in 2 sec is 20 m. Hence, The distance covered in 2 sec is 20 m
Explanation:
Acceleration a = 10 m/s²
Initial velocity u = o
Time t = 2
Using equation of motion
s = ut+ 1/2 at²
Where, u = initial velocity
s = distance
t = time
a = acceleration
We substitute the value in equation (I)
s = 0+1/2 x 10 x 2 x 2
s = 20m
Hence, The distance covered in 2 sec is 20 m.
MARK ME AS BRAINLIEST
Similar questions