Physics, asked by amolkate9153, 10 months ago

A body is acted on by a force given by F=(10+2t)N.The impulse received by the body during the first four seconds is

Answers

Answered by rajkumar707
14

Answer:

Impulse J = \int\limits^t_0{F} \, dt

Here,

F = 10+2t N

J = \int\limits^4_0{(10+2t)} \, dt = [10t + t^2]^4_0 = [(40+16)-(0)] = 56N.s

J = 56N.s

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