Question

A body is acted upon by an upward force of 50N and a horizontal force of 60N. Find the magnitude. and direction of resultant​

Answer 1

$\sqrt{6100}$

as the upward force is 50j in y direction and horizontal force 60i in x direction so resultant vector magnitude is

$\sqrt{ {50}^{2} + {60}^{2} }$

is

$\sqrt{6100}$

Answer 2

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