Question

A body is allowed to fall freely from a height of 1000m . find the time taken to reach the ground (g=10m/s^)

Answer 1

From the formula
$h = ut + \frac{1}{2} g {t}^{2}$
u=0 m/sec
h=1000m
g=10m/sec^2
$h = (0)t + \frac{1}{2} (10) {t }^{2} \\ 1000 = \frac{1}{2} \times 10 \times {t}^{2} \\ \: {t }^{2} = \frac{1000 \times 2}{10} \\ {t }^{2} = 200$
Therefore t=10√2 seconds