A body is allowed to slide down a frictionless track from rest position at its top under gravity. The track ends in a circular loop of diameter d. Then the minimum height of inclined track in terms of d so tht it may complete the loop successfully
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minimum is 2d please Mark brainliest
Meghnateesta:
hi
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Answer:
(5d/4)
Explanation:
Velocity at bottom of loop to do complete circular motion is √5gr , where r is radius.
By applying conservation of energy :
mgh=(1/2)*m(5gd/2)
h=5d/4
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