Question

A body is at y = 8t - 3t^3 from the origin along y-axis. The average velocity during 4s from origin is
1.)4m/s
2.) 2 m/s
3.) - 2 mls
4.) - 4mls.​

Answer 1

Answer:

5m/s

Explanation:

Given: y= 8t − 3t ²

 Average speed =  $\frac{Total distance}{Total time taken}$

Total distance =8(1)−3(1)²

                        = 5m

Total time =1 sec

⇒Average speed =  1 sec X  5 m

​   =5 m/s