Question

A body is displaced from(0,0) to (1m, 1m) along the path x= Y by a force F= (x2j+ yj) N. The work done by this force will be

Answer 1

Answer:

$W=\int\limits {F_{X} } \ dx + {F_{Y} } dy$

  =$\int\limits {x^{2} } \, dx +y dy$

 =(x^3/3+y^2/2)

 apply limits we get W=1/2