Physics, asked by poojakumariduso68811, 1 year ago

a body is drooped from a hoover 180m high.how long does it take to reach the ground?what is it's velocity when it touches the ground?

Answers

Answered by saibharath123star
0

I'm sure we ignore air resistance. Then the height of an object at time t is given by the rule

h(t) = h_0 - (g*t^2)/2,

where h_0 is the initial height and t=0 corresponds to the moment when object was dropped.

Object hits the ground means h(t_1)=0. This is a simple equation:

180 - (10*t_1^2)/2 = 0,

t_1^2 = 36, t_1 = 6(s).

(the solution t_1=-6 isn't suitable, t must be >=0)

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