a body is drooped from a hoover 180m high.how long does it take to reach the ground?what is it's velocity when it touches the ground?
Answers
Answered by
0
I'm sure we ignore air resistance. Then the height of an object at time t is given by the rule
h(t) = h_0 - (g*t^2)/2,
where h_0 is the initial height and t=0 corresponds to the moment when object was dropped.
Object hits the ground means h(t_1)=0. This is a simple equation:
180 - (10*t_1^2)/2 = 0,
t_1^2 = 36, t_1 = 6(s).
(the solution t_1=-6 isn't suitable, t must be >=0)
Similar questions