Question

a body is drop from a height 100m what is its height above the ground after 2 sec on its fall

Answer 1

body falls down from a 100m building when start falling after two seconds it will reach hardly 10ms downwards so it is at the height of 90m

Answer 2

Its height above the ground after 2s is 80 m

Given : A body is dropped from a height 100m.

To find : The height of the object above the ground after 2s.

Solution :

We can simply solve this numerical problem by using the following process. (our goal is to calculate the required height)

Here,

• Initial velocity (u) = 0 m/s (as starts from rest)
• Acceleration (a) = Gravitational acceleration = 10 m/s²
• Time (t) = 2 seconds

According to the formula of kinematics :

Displacement = ut + ½ at²

By, putting the given values, we get :

Displacement of the body = (0 × 2) + (½ × 10 × 2²) = 5×4 = 20 m

Height of the body above the ground :

= Initial height of the body - Displacement of the body

= 100 - 20

= 80 m

(This will be considered as the final result.)

Hence, its height above the ground after 2s is 80 m