Question

a body is droped from a height 122.5m.if it is stopped after 3 seconds and again released.the further time of decent is...(g=9.8m/s^2)

Answer 1

after 3 sec, d = 0 + 1/2 (9.8) (3^2) = 44.1 m

so it's new height = 122.5 - 44.1 = 78.4 m

so 78.4 = 0 + 1/2 (9.8) t^2

=> t^2 = 16 => t = 4 sec

Answer 2

Answer:

hope this helps u mate....,