Question

A body is dropped freely. After 2 seconds another body is dropped from the same height. The

distance of separation between them after 10 more seconds is(g=10ms-2

)​

Answer 1

Explanation:

branely not accepted this answer when i texted so kept screenshot which i sloved.

Answer 2

Answer:

220 m

Explanation:

First Body :-

S1 =UT +1/2 at^2

= 1/2 at^2

=1/2 × 10 × 12 × 12 ( T = 10+ 2 =12)

=720

Second Body:-

S2=1/2 at^2

= 1/2 × 10 × 10 × 10

= 500

S1 - S2 = 720 - 500

=220