Question

A body is dropped froin height X, it reached the ground in 10 s. What is the velocity
when it is touching the surface of the earth?​

Answer 1

Answer:

Yes !!!

Take your answer.

The height of the tower is 20 m.

Explanation:

Given,

u=0m/s

v=20m/s

g=10m/s  

2

 

From 3rd equation of motion,

2gh=v  

2

−u  

2

 

h=  

2g

v  

2

−u  

2

 

​  

 

h=  

2×10

20×20−0×0

​  

 

h=20m

The height of the tower is 20m.

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Answer 2

Answer:

A body is dropped froin height X, it reached the ground in 10 s. What is the velocity

when it is touching the surface of the earth?

Explanation:

h=x

t=10s

h=20m