a body is dropped from a balloon moving up with it is at a height of 74.4 if it takes 6 seconds to reach the ground what is the velocity of the balloon
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we know s=ut+1/at^2
s=74.4
t=6sec
taking g= 10m/s
by solving the first equation we got u = -19.6m/s
here negetive sign show that the body will move upword when released due to law of inertia.
final velocity
v=u+at
=-19.6+(10×6)
=-19.6+60
=40.4m/s
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