A body is dropped from a certain height and acquired a speed of 20 m s–1 when reaches the ground . Find
distance covered in last 1 sec
Answers
Step-by-step explanation:
We have,
v=20m/s
Then,
v=u+at
20=0+10t
20/10=t
2=t
Total distance covered in 2 seconds = v^2=u^2+2as
= 20^2= 0+ 2*10*s
=400/20=s
= 20=s
Total distance covered in first 1 second = s=ut+1/2at^2
= s=0*t+1/2*10*1
= s=5m
= s=5m
Therefore, Distance covered in last 1 second=Total distance travelled-Total
distance covered in first one second
= 20-5=15m
Therefore, Distance covered in last 1 second is 15 m
Answer:
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