Physics, asked by Munmoon1481, 1 year ago

A body is dropped from a certain height h ( h is very large) and second body is thrown downward with velocity of 5 m/s simultaneously

Answers

Answered by aisha6067
14

apply to s=ut+[1/2]at^2

s1=0x3+[1/2]x10x3x3
s1=30m

S2=5x3+[1/2]x10x3x3
S2=15+30=45m

difference=15m

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