A body is dropped from a certain height then the time taken to cover first half and second half of the distance is
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If it takes time “T” to reach the ground then,
H = 0.5gT²
T = √(2H/g)
If it takes time “t” to travel first half of the journey then,
0.5H = 0.5gt²
H = gt²
t = √(H/g)
Time taken to cover second half of the journey is = T - t
= √(2H/g) - √(H/g)
= √(H/g)×(√(2) - 1)
Explanation:
Hope u understood but some how i was jst trying
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