Question

a body is dropped from a height 122.5 m if it stopped after 3sec and again released the furether time of desent

Answer 1

Answer:

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Explanation:

In 3sec the body descends

s=12gt2=12×10×32=45 ms=12gt2=12×10×32=45 m

The distance left,

h=122.5−45=77.5 mh=122.5-45=77.5 m  

Time taken in further descent,

t=2hg−−√=2×77.510−−−−−√=3.94 s