Question

A body is dropped from a height 'h' with an initial speed zero reaches the ground with a velocity of 3 km
Another body of the same mass was dropped from the same height h with an initial speed 4 mt will reach
the ground with a velocity of​

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a body dropped from a height h with an initial speed zero reaches the groun

a body dropped from a height h with an initial speed zero reaches the ground with a speed of 3 km/hr. Another body of same mass dropped with same height h with an initial speed of 4 km/s will reach ground with a speed of

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A)

first body inital velocity u=0

speed-3km/hr

second body

initial speed =4km/s

body is dropped from height h

so a=g=10ms^2

v^2=u^2+2gh

3^2=0+20h

9=20h

h=9/20m

s=9/20m

second object is also dropped from same height,therefore h=9/20m

u=4 km/hr

v^2=u^2+2gh

=4^2+2(10)(9/20)

=5 km/hr

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