Question

a body is dropped from a height h1.If it is rebounded to a height h2 then the coefficient of restitution

Answer 1

When a body is dropped from a height h1, The velocity before reaching the ground is

v = $\sqrt{2gh1}$

where g is the gravitational constant whose value is 9.81 m2/sec

When the ball strikes the ground and bounces back to the height h2, The velocity just after impact was v' given as

v' = $\sqrt{2gh2}$

Coefficient of Restitution = $\frac{\sqrt{v'}}{\sqrt{v} }$ = $\sqrt{\frac{h2}{h1}}$

Coefficient of Restitution = $\frac{\sqrt{2gh2}}{\sqrt{2gh1} }$ = $\sqrt{\frac{h2}{h1}}$

Here is the solution, I have attached, hope it will help you.