Question

A body is dropped from a height of 100m find the position of the body from the ground after 3 seconds

Plz give answer with method

Answer 1

The acceleration due to the Earth’s gravity is approximately

9.81

−2

9.81

m

s

−

2

.

The velocity can be found from the formula

=+

v

=

u

+

a

t

Here

v

is the final velocity,

u

is the initial velocity (which in this case is presumably zero),

a

the acceleration and

t

the time in seconds.

Putting in the two numbers we have, we get

=0+9.81∗3

v

=

0

+

9.81

∗

3

The velocity after three seconds is therefore

29.4

−1

29.4

m

s

−

1

, about 66mph.

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