Question

A body is dropped from a height of 100m . It's velocity at the ground will be

Answer 1

Answer:

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Answer 2

Given:-

▪︎Initial velocity(u)=0

▪︎Height(h)=100m

▪︎Acceleration due to gravity(g)=9.8m/s²

To find:-

▪︎Final velocity(v)

Solution:-

By using the 3rd equation of motion,when u=0,we get---

=>v²=2gh

=>v²=2×100×9.8

=>v²=1960

=>v=44.27m/s

Thus,velocity of the body at the ground is 44.27m/s.