Question

A body is dropped from a height of 16m the body strikes the ground and loses 25% of its velocity. the body rebounds to a height of
a-12m b-9m c-4m d-8m

Answer 1

Use formula for conservation of energy kinetic energy = potential energy. v=√2gh i. e. 4√20m/s.

25% of it will be √20m/s. hence final velocity is (4-1)√20m/s that'll be 3√20m/s.Again using law of conservation of energy mgh=1/2mv^2

putting values in above equation we get 9m as our answer.

Answer 2

Answer:

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