Question

A body is dropped from a top of the tower it aquairs velocity of 20 ms on reaching the ground calculate the height of the tower.​

Answer 1

Given:-

initial velocity(u)=0

final velocity(v)= 20 m/s

acceleration due to gravity(g)=9.8m/s²

To find:-

Height of the tower(h)

Solution:-

By using v²-u²=2gh,we get------

(20)²-0= 2×9.8×h

400= 19.6h

h=400/19.6

h=20.4m

Note:-If we take acceleration due to gravity as 10m/s²,the the height of the tower will be 20m.