Question

A body is dropped from balloon moving up with velocity of 4m/s , when the balloon is at 120m from the ground. The height of the body after 5s f4om the ground is?

Answer 1

Answer:

The height of the body is 17.5 m.

Explanation:

Given that,

Velocity = 4 m/s

Height = 120 m

Time = 5 s

We need to calculate the height of the body

Using equation of motion

$s=h-(ut+\dfrac{1}{2}gt^2)$

Where, u = initial velocity

h = height

g = acceleration due to gravity

Put the value in the equation

$s=120-(-4)\times5+\dfrac{1}{2}\times9.8\times5^2)$

$s=120-(-20+122.5)$

$s=140-122.5=17.5\ m$

Hence, The height of the body is 17.5 m.