a body is dropped from height(h) and takes time(t) to reach the ground.if the acceleration due to gravity is given by 'g' write an expression to find the value of h
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Answer:
(3h)/4 is the required answer.
Explanation:
For a freefall,
Acceleration , a=gm/s2
Initial velocity , u=0m/s
Let the distance travelled by the ball be x.
Applying second equation of motion,
s=ut+(1/2)at2
x=0+(1/2)gt2
Substituting the the value of t as (T/2),
x=(1/2)g(T2/4)
{ As per the question,
h=(1/2)gT2
Find out the value of T from the above expression and put it. }
This implies, x=h/4 .
Now, the height of the ball from the ground will be equal to (h - x).
Therefore (3h)/4 is the required answer.
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