Question

A body is dropped from height H, time taken to cover the second half of the journey is:
Ans: $\sqrt{2H/g} * 1/(\sqrt{2}-1)$
Explanation please!

Answer 1

H=0.5gT²

T=(2H/g)

If it takes time “t” to travel first half of the journey then,

0.5H = 0.5gt²

H = gt²

t=(H/g)

Time taken to cover the second half of the journey is = T - t

=(2H/g)−(H/g)

=(H/g)(√(2)−1)