A body is dropped from height H. What is the time taken to cover second half of the journey?
1. 2√(2H/g) 2. √(H/g) 3. √(H/g)*(√2-1) 4. √(2H/g)*(1/(√2-1))
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If it takes time “T” to reach the ground then,
H = 0.5gT²
T = √(2H/g)
If it takes time “t” to travel first half of the journey then,
0.5H = 0.5gt²
H = gt²
t = √(H/g)
Time taken to cover second half of the journey is = T - t
= √(2H/g) - √(H/g)
= √(H/g)×(√(2) - 1)
Correct option is (3)
H = 0.5gT²
T = √(2H/g)
If it takes time “t” to travel first half of the journey then,
0.5H = 0.5gt²
H = gt²
t = √(H/g)
Time taken to cover second half of the journey is = T - t
= √(2H/g) - √(H/g)
= √(H/g)×(√(2) - 1)
Correct option is (3)
rishilaugh:
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