A body is dropped from rest from a height h. It covers a distance 9h in the last second of fall. The height h is_m
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Answer:If total distance covered by the body is H then the formula is
h = ut + 1/2at2 for total distance covered by the body.
And distance covered in nth second by the body is given by
h = u + a/2(2n-1)
for u = 0,
h= a/2(2n-1) and h=1/2at2. here a= g= 10m/s2.
if total time is t seconds, the last second will be tth second. and the distance covered in the tth second is 9h/25.
Put the values in the two equations and solve them and you will get the answer
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