Math, asked by akshita88990, 2 months ago

a body is dropped from rest from height h gravity the velocity v just before Collision with earth will be given by
a)v=u+gt
b)v=½gt²
c)v²=2gh
d)v²=u²+2gh​

Answers

Answered by amitnrw
1

Given : a body is dropped from rest from height h gravity

the velocity v just before Collision with earth

To Find : Velocity V

a)v=u+gt

b)v=½gt²

c)v²=2gh

d)v²=u²+2gh​

Solution:

PE at height h  = mgh

KE at height h = 0   as at rest

TE = PE + KE = mgh

PE at earth = 0  as h = 0

KE = (1/2)mv²

TE = (1/2)mv²

Equate Total Energy

(1/2)mv² =  mgh

=> v² =  2gh

Hence v²=2gh is the correct answer

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