A Body is dropped from rest from height of 200m first on the earth and then on the moon. Assuming the acceleration due to gravity at moon as one sixth as that on the earth, calculate the ratio of their velocities of reaches to
the surfaces of earth and moon.
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Answer:1 st case 200=v*v/2g
2 nd case 200=v*v/<2g/6>
to find
1 st case /2 nd case
after cancelling
=2g/<2g/6>
1*6/1
6/1
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