Physics, asked by shaktimaanrj13, 3 months ago

A body is dropped from rest from height of h = 5.0 m
After rebounding twice from a horizontal floor, to what
height will it rise if coefficient of restitution is 0.8?​

Answers

Answered by sonuvuce
1

The body will rise to height 2.048 m after rebounding twice.

Explanation:

Given:

Body is dropped from height of 5 m

Coefficient of restitution is 0.8

To find out:

The height to which the body will rise after rebounding twice

Solution:

h=5 m

e=0.8

When the body is dropped then after first rebounding it will reach height

h_1=e^2h

And after second rebounding it will reach the height

h_2=e^2h_1

\implies h_2=e^2\times e^2h

\implies h_2=e^4h

\implies h_2=0.8^4\times 5

\implies h_2=2.048 m

Hope this answer is helpful.

Know More:

Q: A ball is dropped on to a floor from a height of 10 m. It rebounds to a height of 2.5 m . If the ball is in contact with the floor for 00.01 sec. What is the average acceleration during contact?

Click Here: https://brainly.in/question/216076

Q: A rubber ball of mass 50 g falls from a height of 10 cm and rebounds to a height of 50 cm. Determine the change in linear momentum and average force between the ball and the ground, taking time of contact as 0.1 s

Click Here: https://brainly.in/question/504361

Similar questions