a body is dropped from the height of 100 M find its velocity while touching the ground (giving acceleration due to the gravity is 10 m s -2)
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Answered by
0
.v^2-u^2=2as v^2=2×100×10. V^2=2000 v=44.72
Answered by
4
v2 = u2 + 2gh
u = 0
h = 100m
so, v2 = 0 + 2×10×100
v2 = 2000
so, v = 20 root(5)
u = 0
h = 100m
so, v2 = 0 + 2×10×100
v2 = 2000
so, v = 20 root(5)
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