A body is dropped from the roof of a building 10 m high calculate the time of fall and the speed with which it hits the ground
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Answer:
speed=14.14m/s
time=1.414sec
Step-by-step explanation:
body is dropped so initial velocity is 0
let speed with it fall is v
acceleration due to gravity is g
from equation of motion
v^2=u^2+2as
v^2=0+2(10)(10)
v^2=200
v=14.14m/s
let time of fall is t
s=ut+1/2at^2
10=1/2(10)t^2
t^2=2
t=1.41sec
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