Question

a body is dropped from the top of a tower, find the ratio of the distance travelled by it in the "7th" and 10th second of its motion.

Answer 1

Answer:

Hey user !!

Here's the answer you are looking for

Let the height of the tower is h and time taken by it to reach the ground from height h is t.

Since, it is dropped, it's initial velocity (u) = 0

Using the second equation of motion,

The last second means at t = √(h/5)th second.

So, at t = √(h/5)th second, the ball travels 15m

Therefore, the height of the tower is 20m.

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