Question

A body is dropped from the top of a tower. It acquires a velocity 20 ms–1 on reaching the ground. Calculate the height of tower. (g = 10 ms–2)

Answer 1

Height of tower = 20m

Explanation:

Given that a body is dropped from the top of a tower. Its velocity is 20 m/s on reaching the ground.  

So we have Initial velocity u = 0, final velocity v = 20 m/s, and g = 10 m/s2

v = u + gt

20 = 0 + 10t

Time = 2 seconds

height = 1/2 gt^2

h = 1/2 * 10 * 2 * 2

h = 20 metres

Answer 2

Answer:

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Explanation:

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