Question

A body is dropped from the top of a tower.  It acquires a velocity 20 m/s on reaching the ground. Calculate the height of the tower. What is force of impact when it touches the ground, if the mass of the body is 10kg.(g=10m/s2)​

Answer 1

Answer:

Height= 20m, Force of impact = 100N

Explanation:

U = 0m/s

V = 20m/s

g= 10m/s2

Now,

v square - u square = 2gh

20*20 - 0= 2*10h

400 = 20h

h= 400/20

h= 20m

Now,

F=mg

= 10*10

= 100N