A body is dropped trom a certain height and the distance covered by an in time T seconds is given by S=1/2gt^2 F ind the velocity and acceleration of the body at the end of 3s. (Take g = 10ms)
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v= u+gt ,
since u is zero " v= gt downwards.
after 3 secs v = 10x3 = 30 Msec^-2
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