Question

a body is dropped with some height takes time t to reach ground. find time taken to cover the distance equal to 1/4 of the height.​

Answer 1

Answer:

√h/4√5

Given,

u = 0m/s

g=10m/s^2

Let the height be h

So,

for height h , time taken = t

for height h/4 , time taken = t/4

We know,

s=ut+1/2gt^2

=>h= 1/2*10t^2

=>h=5t^2

=>t^2=h/5

=>t=√(h/5)

=>t/4=√(h/5)/4

=>t/4=√h/4√5