Question

A body is executing SHM with amplitude a and time period
T. The ratio of kinetic and potential energy when
displacement from the equilibrium position is half the amplitude
(1) 1:1
(2) 2:1
(3) 1:3
(4) 3:1​

Answer 1

Answer:

Explanation:see the attachment below

Answer 2

Dear Student,

◆ Answer -

(4) KE:PE = 3:1

● Explaination -

When displacement of the particle is half the amplitude.

PE = kx²/2

PE = k × (a/2)² / 2

PE = ka²/8

For SHM, total mechanical energy is always constant.

KE + PE = ka²/2

KE + ka²/8 = ka²/2

KE = ka²/2 - ka²/8

KE = 3ka²/8

Ratio of kinetic and potential energy is -

KE/PE = (3ka²/8) / (ka²/8)

KE/PE = 3

Therefore, ratio of KE:PE is 3:1.

Thanks dear...