A body is experiencing an atmospheric pressure of
1.01 x 10' N/m-on the surface of a pound. The
body will experience double of the previous pressure
if it is brought to a depth of (given density of pound
water =1.03 x 10 kg/m2, g = 10 m/s2)
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According to ,p is equal to hdg
Atom.pressure at surface of pond is 1.01 into 10 N/m
let height h inside the pond where atom.p is 2 into 1.01 into 10
2.02 into 10
By
atmos.p is hdg
- 20.2 is equal to h.(10.3 kg/m^2). 10m/s^
- 20.2/103 is equal to h
- so , h is equal to 0.196 m aproximate 0.10 m answer
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